Capture all consecutive all-caps words with regex in python?

Question

I am trying to match all consecutive all caps words/phrases using regex in Python. Given the following:

    text = \"The following words are ALL CAPS. The follow         


        

Answer 1

This one does the job:

import re
text = "tHE following words aRe aLL CaPS. ThE following word Is in CAPS."
matches = re.findall(r"(\b(?:[A-Z]+[a-z]?[A-Z]*|[A-Z]*[a-z]?[A-Z]+)\b(?:\s+(?:[A-Z]+[a-z]?[A-Z]*|[A-Z]*[a-z]?[A-Z]+)\b)*)",text)
print matches

Output:

['tHE', 'aLL CaPS', 'ThE', 'Is', 'CAPS']

Explanation:

(           : start group 1
  \b        : word boundary
  (?:       : start non capture group
    [A-Z]+  : 1 or more capitals
    [a-z]?  : 0 or 1 small letter
    [A-Z]*  : 0 or more capitals
   |        : OR
    [A-Z]*  : 0 or more capitals
    [a-z]?  : 0 or 1 small letter
    [A-Z]+  : 1 or more capitals
  )         : end group
  \b        : word boundary
  (?:       : non capture group
    \s+     : 1 or more spaces
    (?:[A-Z]+[a-z]?[A-Z]*|[A-Z]*[a-z]?[A-Z]+) : same as above
    \b      : word boundary
  )*        : 0 or more time the non capture group
)           : end group 1