Can a decorator of an instance method access the class?

Question

I have something roughly like the following. Basically I need to access the class of an instance method from a decorator used upon the instance method in its definition.

Answer 1

The problem is that when the decorator is called the class doesn't exist yet. Try this:

def loud_decorator(func):
    print("Now decorating %s" % func)
    def decorated(*args, **kwargs):
        print("Now calling %s with %s,%s" % (func, args, kwargs))
        return func(*args, **kwargs)
    return decorated

class Foo(object):
    class __metaclass__(type):
        def __new__(cls, name, bases, dict_):
            print("Creating class %s%s with attributes %s" % (name, bases, dict_))
            return type.__new__(cls, name, bases, dict_)

    @loud_decorator
    def hello(self, msg):
        print("Hello %s" % msg)

Foo().hello()

This program will output:

Now decorating 
Creating class Foo(,) with attributes {'__module__': '__main__', '__metaclass__': , 'hello': }
Now calling  with (<__main__.Foo object at 0xb74ea1ac>, 'World'),{}
Hello World

As you see, you are going to have to figure out a different way to do what you want.