C++ Get name of type in template

Question

I\'m writing some template classes for parseing some text data files, and as such it is likly the great majority of parse errors will be due to errors in the data file, whic

Answer 1

typeid(uint8_t).name() is nice, but it returns "unsigned char" while you may expect "uint8_t".

This piece of code will return you the appropriate type

#define DECLARE_SET_FORMAT_FOR(type) \
    if ( typeid(type) == typeid(T) ) \
        formatStr = #type;

template
static std::string GetFormatName()
{
    std::string formatStr;

    DECLARE_SET_FORMAT_FOR( uint8_t ) 
    DECLARE_SET_FORMAT_FOR( int8_t ) 

    DECLARE_SET_FORMAT_FOR( uint16_t )
    DECLARE_SET_FORMAT_FOR( int16_t )

    DECLARE_SET_FORMAT_FOR( uint32_t )
    DECLARE_SET_FORMAT_FOR( int32_t )

    DECLARE_SET_FORMAT_FOR( float )

    // .. to be exptended with other standard types you want to be displayed smartly

    if ( formatStr.empty() )
    {
        assert( false );
        formatStr = typeid(T).name();
    }

    return formatStr;
}