I am using ruby 1.8.7.
p = lambda { return 10;}
def lab(block)
puts \'before\'
puts block.call
puts \'after\'
end
lab p
Above code output
The {} block includes the context in which it is given, so the return tries to return from the line lab { return 10; }. You can actually make this work (sometimes even in a useful manner) by placing that line inside a method, which will then return (i.e. "after" is not printed).
To return the 10 to block.call, omit the return (or substitute next).