Version number comparison in Python

Question

I want to write a cmp-like function which compares two version numbers and returns -1, 0, or 1 based on their compared va

Answer 1

Remove trailing .0 and .00 with regex, split and use cmp function which compares arrays correctly:

def mycmp(v1,v2):
 c1=map(int,re.sub('(\.0+)+\Z','',v1).split('.'))
 c2=map(int,re.sub('(\.0+)+\Z','',v2).split('.'))
 return cmp(c1,c2)

And, of course, you can convert it to a one-liner if you don't mind the long lines.