grep last match and it's following lines

Question

I\'ve learnt how to grep lines before and after the match and to grep the last match but I haven\'t discovered how to grep the last match

Answer 1

using awk instead:

awk '/pattern/{m=$0;l=NR}l+1==NR{n=$0}END{print m;print n}' foo.log

small test, find the last line matching /8/ and the next line of it:

kent$  seq 20|awk '/8/{m=$0;l=NR}l+1==NR{n=$0}END{print m;print n}'
18
19