Spread Syntax vs Rest Parameter in ES2015 / ES6

Question

I am confused about the spread syntax and rest parameter in ES2015. Can anybody explain the difference between them with proper examples?

Answer 1

considering 3 scenarios

1] without using any operator

function add(x, y) {
  return x + y;
}

add(1, 2, 3, 4, 5) // returns 3  (function will takes first 2 arg only)

2] with rest operator

function add(...args) {
  let result = 0;

  for (let arg of args) result += arg;

  return result
}

add(1) // returns 1
add(1,2) // returns 3
add(1, 2, 3, 4, 5) // returns 15

- we can gather any number of arguments into an array

3] with spread operator

const arr = ["Joy", "Wangari", "Warugu"];
const newArr = ["joykare", ...arr];

The value of newArr will be [ 'joykare', 'Joy', 'Wangari', 'Warugu' ]

another one

function add(a, b, c) {
  return a + b + c ;
}
const args = [1, 2, 3];

add(...args);

-We have been using arrays to demonstrate the spread operator, 
but any iterable also works. So, if we had a 
string const str = 'joykare', [...str] translates to [ 'j', 'o', 'y', 'k', 'a', 'r', 'e' ]