Is it possible to query the current state of the matplotlib color cycle? In other words is there a function get_cycle_state that will behave in the following wa
Sure, this will do it.
#rainbow
import matplotlib.pyplot as plt
import numpy as np
x = np.linspace(0,2*np.pi)
ax= plt.subplot(1,1,1)
ax.plot(np.sin(x))
ax.plot(np.cos(x))
rainbow = ax._get_lines.color_cycle
print rainbow
for i, color in enumerate(rainbow):
if i<10:
print color,
Gives:
r c m y k b g r c m
Here is the itertools function that matplotlib uses itertools.cycle
Edit: Thanks for the comment, it seems that it is not possible to copy an iterator. An idea would be to dump a full cycle and keep track of which value you are using, let me get back on that.
Edit2: Allright, this will give you the next color and make a new iterator that behaves as if next was not called. This does not preserve the order of coloring, just the next color value, I leave that to you.
This gives the following output, notice that steepness in the plot corresponds to index, eg first g is the bottomest graph and so on.
#rainbow
import matplotlib.pyplot as plt
import numpy as np
import collections
import itertools
x = np.linspace(0,2*np.pi)
ax= plt.subplot(1,1,1)
def create_rainbow():
rainbow = [ax._get_lines.color_cycle.next()]
while True:
nextval = ax._get_lines.color_cycle.next()
if nextval not in rainbow:
rainbow.append(nextval)
else:
return rainbow
def next_color(axis_handle=ax):
rainbow = create_rainbow()
double_rainbow = collections.deque(rainbow)
nextval = ax._get_lines.color_cycle.next()
double_rainbow.rotate(-1)
return nextval, itertools.cycle(double_rainbow)
for i in range(1,10):
nextval, ax._get_lines.color_cycle = next_color(ax)
print "Next color is: ", nextval
ax.plot(i*(x))
plt.savefig("SO_rotate_color.png")
plt.show()
Console
Next color is: g
Next color is: c
Next color is: y
Next color is: b
Next color is: r
Next color is: m
Next color is: k
Next color is: g
Next color is: c
