Extract substring using regexp in plain bash

Question

I\'m trying to extract the time from a string using bash, and I\'m having a hard time figuring it out.

My string is like this:

US/Central - 10:26 PM          


        

Answer 1

    echo "US/Central - 10:26 PM (CST)" | sed -n "s/^.*-\s*\(\S*\).*$/\1/p"

-n      suppress printing
s       substitute
^.*     anything at the beginning
-       up until the dash
\s*     any space characters (any whitespace character)
\(      start capture group
\S*     any non-space characters
\)      end capture group
.*$     anything at the end
\1      substitute 1st capture group for everything on line
p       print it