Java: Calling a super method which calls an overridden method

Question

public class SuperClass
{
    public void method1()
    {
        System.out.println(\"superclass method1\");
        this.method2();
    }

    public void method2(         


        

Answer 1

Since the only way to avoid a method to get overriden is to use the keyword super, I've thought to move up the method2() from SuperClass to another new Base class and then call it from SuperClass:

class Base 
{
    public void method2()
    {
        System.out.println("superclass method2");
    }
}

class SuperClass extends Base
{
    public void method1()
    {
        System.out.println("superclass method1");
        super.method2();
    }
}

class SubClass extends SuperClass
{
    @Override
    public void method1()
    {
        System.out.println("subclass method1");
        super.method1();
    }

    @Override
    public void method2()
    {
        System.out.println("subclass method2");
    }
}

public class Demo 
{
    public static void main(String[] args) 
    {
        SubClass mSubClass = new SubClass();
        mSubClass.method1();
    }
}

Output:

subclass method1
superclass method1
superclass method2