Java: Calling a super method which calls an overridden method

Question

public class SuperClass
{
    public void method1()
    {
        System.out.println(\"superclass method1\");
        this.method2();
    }

    public void method2(         


        

Answer 1

If you don't want superClass.method1 to call subClass.method2, make method2 private so it cannot be overridden.

Here's a suggestion:

public class SuperClass {

  public void method1() {
    System.out.println("superclass method1");
    this.internalMethod2();
  }

  public void method2()  {
    // this method can be overridden.  
    // It can still be invoked by a childclass using super
    internalMethod2();
  }

  private void internalMethod2()  {
    // this one cannot.  Call this one if you want to be sure to use
    // this implementation.
    System.out.println("superclass method2");
  }

}

public class SubClass extends SuperClass {

  @Override
  public void method1() {
    System.out.println("subclass method1");
    super.method1();
  }

  @Override
  public void method2() {
    System.out.println("subclass method2");
  }
}

If it didn't work this way, polymorphism would be impossible (or at least not even half as useful).