Find duplicate element in array in time O(n)

Question

I have been asked this question in a job interview and I have been wondering about the right answer.

You have an array of numbers from 0 to n-1, one o

Answer 1

Traverse through the array and check the sign of array[abs(array[i])], if positive make it as negative and if it is negative then print it, as follows:

import static java.lang.Math.abs;

public class FindRepeatedNumber {

    private static void findRepeatedNumber(int arr[]) {
        int i;
        for (i = 0; i < arr.length; i++) {
            if (arr[abs(arr[i])] > 0)
                arr[abs(arr[i])] = -arr[abs(arr[i])];
            else {
                System.out.print(abs(arr[i]) + ",");
            }
        }
    }

    public static void main(String[] args) {
        int arr[] = { 4, 2, 4, 5, 2, 3, 1 };
        findRepeatedNumber(arr);
    }
}

Reference: http://www.geeksforgeeks.org/find-duplicates-in-on-time-and-constant-extra-space/