How to determine if a number is odd in JavaScript

Question

Can anyone point me to some code to determine if a number in JavaScript is even or odd?

Answer 1

this works for arrays:

function evenOrOdd(numbers) {
  const evenNumbers = [];
  const oddNumbers = [];
  numbers.forEach(number => {
    if (number % 2 === 0) {
      evenNumbers.push(number);
    } else {
      oddNumbers.push(number);
    }
  });

  console.log("Even: " + evenNumbers + "\nOdd: " + oddNumbers);
}

evenOrOdd([1, 4, 9, 21, 41, 92]);

this should log out: 4,92 1,9,21,41

for just a number:

function evenOrOdd(number) {
  if (number % 2 === 0) {
    return "even";
  }

  return "odd";
}

console.log(evenOrOdd(4));

this should output even to the console