How to determine if a number is odd in JavaScript

Question

Can anyone point me to some code to determine if a number in JavaScript is even or odd?

Answer 1

A more functional approach in modern javascript:

const NUMBERS = "nul one two three four five six seven ocho nueve".split(" ")

const negate = f=> (...args)=> !f(...args)
const isOdd  = n=> NUMBERS[n % 10].indexOf("e")!=-1
const isEven = negate(isOdd)