I\'m reading Kotlin Coroutine and know that it is based on suspend
function. But what does suspend
mean?
Coroutine or function gets
To understand what exactly it means to suspend a coroutine, I suggest you go through this code:
import kotlinx.coroutines.Dispatchers.Unconfined
import kotlinx.coroutines.launch
import kotlinx.coroutines.runBlocking
import kotlin.coroutines.Continuation
import kotlin.coroutines.resume
import kotlin.coroutines.suspendCoroutine
var continuation: Continuation? = null
fun main() = runBlocking {
launch(Unconfined) {
val a = a()
println("Result is $a")
}
10.downTo(0).forEach {
continuation!!.resume(it)
}
}
suspend fun a(): Int {
return b()
}
suspend fun b(): Int {
while (true) {
val i = suspendCoroutine { cont -> continuation = cont }
if (i == 0) {
return 0
}
}
}
The Unconfined
coroutine dispatcher eliminates the magic of coroutine dispatching and allows us to focus directly on bare coroutines.
The code inside the launch
block starts executing right away on the current thread, as a part of the launch
call. What happens is as follows:
val a = a()
b()
, reaching suspendCoroutine
.b()
executes the block passed to suspendCoroutine
and then returns a special COROUTINE_SUSPENDED
value. This value is not observable through the Kotlin programming model, but that's what the compiled Java method does.a()
, seeing this return value, itself also returns it.launch
block does the same and control now returns to the line after the launch
invocation: 10.downTo(0)...
Note that, at this point, you have the same effect as if the code inside the launch
block and your fun main
code are executing concurrently. It just happens that all this is happening on a single native thread so the launch
block is "suspended".
Now, inside the forEach
looping code, the program reads the continuation
that the b()
function wrote and resumes
it with the value of 10
. resume()
is implemented in such a way that it will be as if the suspendCoroutine
call returned with the value you passed in. So you suddenly find yourself in the middle of executing b()
. The value you passed to resume()
gets assigned to i
and checked against 0
. If it's not zero, the while (true)
loop goes on inside b()
, again reaching suspendCoroutine
, at which point your resume()
call returns, and now you go through another looping step in forEach()
. This goes on until finally you resume with 0
, then the println
statement runs and the program completes.
The above analysis should give you the important intuition that "suspending a coroutine" means returning the control back to the innermost launch
invocation (or, more generally, coroutine builder). If a coroutine suspends again after resuming, the resume()
call ends and control returns to the caller of resume()
.
The presence of a coroutine dispatcher makes this reasoning less clear-cut because most of them immediately submit your code to another thread. In that case the above story happens in that other thread, and the coroutine dispatcher also manages the continuation
object so it can resume it when the return value is available.