Polymorphic method in Constructor (Java)

Question

Class A calls the public method f() in the Constructor. Class B overrides method f() with its own implementation.

Suppose you inta

Answer 1

When new B(), A's Constructor is called implicitly or called via super(). Although it is defined in Class A, actually the current class is B.

Try add the below debug info into A's constructor and functions.

System.out.println(this.getClass());

In your case, the function f() in Class A has been overriden by Class B, so the function in A() will call B()'s implementation. However, if the f() is a private method and can not be override by B, the A.f() will be called with higher priorities.

But as others commented, it's not a good practice.