Under Linux, how do I find out which process is using the swap space more?
Another script variant avoiding the loop in shell:
#!/bin/bash
grep VmSwap /proc/[0-9]*/status | awk -F':' -v sort="$1" '
{
split($1,pid,"/") # Split first field on /
split($3,swp," ") # Split third field on space
cmdlinefile = "/proc/"pid[3]"/cmdline" # Build the cmdline filepath
getline pname[pid[3]] < cmdlinefile # Get the command line from pid
swap[pid[3]] = sprintf("%6i %s",swp[1],swp[2]) # Store the swap used (with unit to avoid rebuilding at print)
sum+=swp[1] # Sum the swap
}
END {
OFS="\t" # Change the output separator to tabulation
print "Pid","Swap used","Command line" # Print header
if(sort) {
getline max_pid < "/proc/sys/kernel/pid_max"
for(p=1;p<=max_pid;p++) {
if(p in pname) print p,swap[p],pname[p] # print the values
}
} else {
for(p in pname) { # Loop over all pids found
print p,swap[p],pname[p] # print the values
}
}
print "Total swap used:",sum # print the sum
}'
Standard usage is script.sh
to get the usage per program with random order (down to how awk
stores its hashes) or script.sh 1
to sort the output by pid.
I hope I've commented the code enough to tell what it does.