Print value and address of pointer defined in function?

Question

I think this is a really easy thing to code, but I\'m having trouble with the syntax in C, I\'ve just programmed in C++.

#include 
#include 

        

Answer 1

#include 
#include 

void pointerFuncA(int* iptr){
/*Print the value pointed to by iptr*/
printf("Value:  %p\n", (void*) iptr );

/*Print the address pointed to by iptr*/

/*Print the address of iptr itself*/
}

int main(){
int iptr = 0;
pointerFuncA( &iptr); 

return 0;
}

I think you are looking at something like this, there is no need to re-define the function again in the main....