Extending typed Arrays (of primitive types like Bool) in Swift 3?

Question

Previously in Swift 2.2 I\'m able to do:

extension _ArrayType where Generator.Element == Bool{
    var allTrue : Bool{
        return !self.contains(false)
    }         


        

Answer 1

Just extend the Collection or the Sequence

extension Collection where Element == Bool { 
    var allTrue: Bool { return !contains(false) }
}

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edit/update:

Xcode 10 • Swift 4 or later

You can use Swift 4 or later collection method allSatisfy

let alltrue = [true, true,true, true,true, true].allSatisfy{$0}  // true

let allfalse = [false, false,false, false,false, false].allSatisfy{!$0} // true

---

extension Collection where Element == Bool {
    var allTrue: Bool { return allSatisfy{ $0 } }
    var allFalse: Bool { return allSatisfy{ !$0 } }
}

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Testing Playground:

[true, true, true, true, true, true].allTrue // true
[false, false, false, false, false, false].allFalse // true