Print 5 items in a row on separate lines for a list?

Question

I have a list of unknown number of items, let\'s say 26. let\'s say

list=[\'a\',\'b\',\'c\',\'d\',\'e\',\'f\',\'g\',\'h\',
\'i\',\'j\',\'k\',\'l\',\'m\',\'n\',\'         


        

Answer 1

If you're working on an iterable (like a file) which is potentially too big to fit in RAM you can use something like this:

from itertools import izip_longest
def chunker(iterable, n, fillvalue=None):
    """Like an itertools.grouper but None values are excluded.

    >>> list(chunker([1, 2, 3, 4, 5], 3))
    [[1, 2, 3], [4, 5]]
    """
    if n < 1:
        raise ValueError("can't chunk by n=%d" % n)
    args = [iter(iterable)] * n
    return (
        [e for e in t if e is not None]
        for t in izip_longest(*args, fillvalue=fillvalue)
    )

with open('some_file') as f:
    for row in chunker(f, 5):
        print "".join(row)

If RAM is not a consideration the answer by ZdaR is preferable as it is considerably faster.