Square of a number being defined using #define

Question

I was just going through certain code which are frequently asked in interviews. I came up with certain questions, if anyone can help me regarding this?

I am totally

Answer 1

It's a macro! So it returns exactly what it substitutes.

i = 4/4*4;   Which is 4...
j = 64/4*4;   Which is 16...

Try this for your macro:

#define square(x) ((x)*(x))