Square of a number being defined using #define

Question

I was just going through certain code which are frequently asked in interviews. I came up with certain questions, if anyone can help me regarding this?

I am totally

Answer 1

That's because the compiler replaces it with:

i=4/4*4; 
j=64/4*4;

i = (4/4)*4 = 1*4 = 4.

j = (64/4)*4 = 16*4 = 64.