How to convert uint8 to string

Question

http://play.golang.org/p/BoZkHC8_uA

I want to convert uint8 to string but can\'t figure out how.

  package main

  import \"fmt\"
  import \"strconv\         


        

Answer 1

There are no automatic conversions of basic types in Go expressions. See https://talks.golang.org/2012/goforc.slide#18. A byte (an alias of uint8) or []byte ([]uint8) has to be set to a bool, number or string.

package main

import (
    . "fmt"
)

func main() {
    b := []byte{'G', 'o'}
    c := []interface{}{b[0], float64(b[0]), int(b[0]), rune(b[0]), string(b[0]), Sprintf("%s", b), b[0] != 0}
    checkType(c)
}

func checkType(s []interface{}) {
    for k, _ := range s {
        // uint8 71, float64 71, int 71, int32 71, string G, string Go, bool true
        Printf("%T %v\n", s[k], s[k])
    }
}

Sprintf("%s", b) can be used to convert []byte{'G', 'o' } to the string "Go". You can convert any int type to a string with Sprintf. See https://stackoverflow.com/a/41074199/12817546.

But Sprintf uses reflection. See the comment in https://stackoverflow.com/a/22626531/12817546. Using Itoa (Integer to ASCII) is faster. See @DenysSéguret and https://stackoverflow.com/a/38077508/12817546. Quotes edited.