C++ - If an object is declared in a loop, is its destructor called at the end of the loop?

Question

In C++, an object\'s destructor is called at the closing \"}\" for the block it was created in, right? So this means that if I have:

while(some_condition)
{
             


        

Answer 1

Yes.

But you could have tested it yourself. This is a language feature that compilers are unlikely to get wrong.

#include 

struct S {
  S() { std::cout << "S::S()\n"; }
  ~S() { std::cout << "S::~S()\n"; }
};

int main () {
  int i = 10;
  while(i--) {
    S s;
  }
}