If I have a constructor Quo
var Quo = function (string) {
this.status = string;
};
and then made a new object using var
When you define a function, it has a property prototype that is used as the [[prototype]] of all of the objects it creates using the new keyword. When you add members to Quo.prototype, all objects created using new Quo() will be able to read the member as if they had it (through their [[prototype]], namely Quo.prototype). On the other hand, if you assign members to Quo directly, you can only access them through Quo itself.
Example:
var Quo = function (status) {
this.status = status;
}
Quo.status = "enlightened";
Quo.get_status = function() {
return this.status;
}
Quo.prototype.get_status = function() {
return this.status;
}
var quo = new Quo("confused");
Quo.get_status(); // "enlightened"
quo.get_status(); // "confused"