Better way to say x == Foo::A || x == Foo::B || x == Foo::C || …?

Question

Let\'s say I have a bunch of well-known values, like this (but const char * is just an example, it could be more complicated):

const char *A = \"A\"         


        

Answer 1

You could use a switch:

switch (some_complicated_expression_with_ugly_return_type) {
  case A: case C: case E: case G:
    // do something
  default:
    // no-op
}

This only works with integer and enum types, note.

For more complex types, you can use C++11's auto, or for C++03, boost's BOOST_AUTO:

auto tmp = some_complicated_expression_with_ugly_return_type;
// or
BOOST_AUTO(tmp, some_complicated_expression_with_ugly_return_type);

if (tmp == A || tmp == C || tmp == E || tmp == G) {
  // ...
}