I was trying to incrementally change the background color of a cell to black, and I found that the Range.Interior.Color method returns a Long which is seemingly arbitrary.
Mark Balhoff´s VBA script works fine. All credits go to him.
In case you´d like to get the color codes/indexes of conditionally formatted cells as well, the code may be amended like this:
'----------------------------------------------------------------
' Function Color
' Purpose Determine the Background Color Of a Cell
' @Param rng Range to Determine Background Color of
' @Param formatType Default Value = 0
' 0 Integer color of cell, not considering conditional formatting color
' 1 Hex color of cell, not considering conditional formatting color
' 2 RGB color of cell, not considering conditional formatting color
' 3 Excel Color Index color of cell, not considering conditional formatting color
' 4 Integer "real" visible color of cell (as the case may be the conditional formatting color)
' 5 Hex "real" visible color of cell (as the case may be the conditional formatting color)
' 6 RGB "real" visible color of cell (as the case may be the conditional formatting color)
' 7 Excel Color Index "real" visible color of cell (as the case may be the conditional formatting color)
' Usage Color(A1) --> 9507341
' Color(A1, 0) --> 9507341
' Color(A1, 1) --> 91120D
' Color(A1, 2) --> 13, 18, 145
' Color(A1, 3) --> 6
'-----------------------------------------------------------------
Function Color(rng As Range, Optional formatType As Integer = 0) As Variant
Dim colorVal As Variant
Select Case formatType
Case 0 To 3
colorVal = Cells(rng.Row, rng.Column).Interior.Color
Case 4 To 7
colorVal = Cells(rng.Row, rng.Column).DisplayFormat.Interior.Color
End Select
Select Case formatType
Case 0
Color = colorVal
Case 1
Color = Hex(colorVal)
Case 2
Color = (colorVal Mod 256) & ", " & ((colorVal \ 256) Mod 256) & ", " & (colorVal \ 65536)
Case 3
Color = Cells(rng.Row, rng.Column).Interior.ColorIndex
Case 4
Color = colorVal
Case 5
Color = Hex(colorVal)
Case 6
Color = (colorVal Mod 256) & ", " & ((colorVal \ 256) Mod 256) & ", " & (colorVal \ 65536)
Case 7
Color = Cells(rng.Row, rng.Column).DisplayFormat.Interior.ColorIndex
End Select
End Function