Python passing list as argument

Question

If i were to run this code:

def function(y):
    y.append(\'yes\')
    return y

example = list()
function(example)
print(example)

Why woul

Answer 1

Its because you called the function before printing the list. If you print the list then call the function and then print the list again, you would get an empty list followed by the appended version. Its in the order of your code.