How to initialize a Thread in Kotlin?

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青春惊慌失措
青春惊慌失措 2021-02-06 21:14

In Java it works by accepting an object which implements runnable :

Thread myThread = new Thread(new myRunnable())

where myRunnable

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  •  忘掉有多难
    2021-02-06 21:53

    Kotlin comes with a standard library function thread, which I'd recommend to use here:

    public fun thread(
        start: Boolean = true, 
        isDaemon: Boolean = false, 
        contextClassLoader: ClassLoader? = null, 
        name: String? = null, 
        priority: Int = -1, 
        block: () -> Unit): Thread
    

    You can use it like this:

    thread {
        Thread.sleep(1000)
        println("test")
    }
    

    It has many optional parameters for e.g. not starting the thread directly by setting start to false.


    Alternatives

    To initialize an instance of class Thread, invoke its constructor:

    val t = Thread()
    

    You may also pass an optional Runnable as a lambda (SAM Conversion) as follows:

    Thread {
        Thread.sleep(1000)
        println("test")
    }
    

    The more explicit version would be passing an anonymous implementation of Runnable like this:

    Thread(Runnable {
        Thread.sleep(1000)
        println("test")
    })
    

    Note that the previously shown examples do only create an instance of a Thread but don't actually start it. In order to achieve that, you need to invoke start() explicitly.

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