PHP: Using a variable inside a double quotes

Question

please check the following code.

$imagebaseurl = \'support/content_editor/uploads/$name\';

The $imagebaseurl is a variable th

Answer 1

I couldn't disagree more with the previous post.

I'd almost go as far to call it bad practice to use

$varname = 'EXAMPLE';

$fulltext = "This is an $varname";

Its more maintainable, from my experience, to utilize a good friend of mine known as sprintf();

define('CONST_NAME', 'This is an example of a better %s');
define('EXAMPLE', sprintf(CONST_NAME, 'practice'));

echo EXAMPLE;

Why? The first one may seem more clear, but the second one is much more re-usable. I recommend utilizing sprintf over the php magic double quote nonesense which exists, literally, in NO other language.

http://php.net/manual/en/function.sprintf.php

This is also the practice used very similar to C#, and many other languages.

See also: https://msdn.microsoft.com/en-us/library/system.string.format(v=vs.110).aspx