Is there a function to round a float in C or do I need to write my own?

Question

Is there a function to round a float in C or do I need to write my own?

float conver = 45.592346543;

I would

Answer 1

To print a rounded value, @Matt J well answers the question.

float x = 45.592346543;
printf("%0.1f\n", x);  // 45.6

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As most floating point (FP) is binary based, exact rounding to one decimal place is not possible when the mathematically correct answer is x.1, x.2, ....

To convert the FP number to the nearest 0.1 is another matter.

Overflow: Approaches that first scale by 10 (or 100, 1000, etc) may overflow for large x.

float round_tenth1(float x) {
  x = x * 10.0f;
  ...
}

Double rounding: Adding 0.5f and then using floorf(x*10.0f + 0.5f)/10.0 returns the wrong result when the intermediate sum x*10.0f + 0.5f rounds up to a new integer.

// Fails to round 838860.4375 correctly, comes up with 838860.5 
// 0.4499999880790710449 fails as it rounds to 0.5
float round_tenth2(float x) {
  if (x < 0.0) {
    return ceilf(x*10.0f + 0.5f)/10.0f;
  }
  return floorf(x*10.0f + 0.5f)/10.0f;
}

Casting to int has the obvious problem when float x is much greater than INT_MAX.

---

Using roundf() and family, available in is the best approach.

float round_tenthA(float x) {
  double x10 = 10.0 * x;
  return (float) (round(x10)/10.0);
}

To avoid using double, simply test if the number needs rounding.

float round_tenthB(float x) {
  const float limit = 1.0/FLT_EPSILON;
  if (fabsf(x) < limit) {
    return roundf(x*10.0f)/10.0f;
  }
  return x;
}