Can I destructure a tuple without binding the result to a new variable in a let/match/for statement?

Question

I\'d like to destructure a tuple and assign part of the result to a new variable and assign another part of the result to an existing.

The following code illustrates

Answer 1

No.

Destructuring is something you can only do with patterns; the left-hand side of an assignment is not a pattern, hence you can't destructure-and-assign.

See proto-RFC 372 (Destructuring assignment) which discusses the possibility of adding this feature.