In C, why is sizeof(char) 1, when 'a' is an int?

Question

I tried

printf(\"%d, %d\\n\", sizeof(char), sizeof(\'c\'));

and got 1, 4 as output. If size of a character is one, why does \'c\'

Answer 1

It is the normal behavior of the sizeof operator (See Wikipedia):

• For a datatype, sizeof returns the size of the datatype. For char, you get 1.
• For an expression, sizeof returns the size of the type of the variable or expression. As a character literal is typed as int, you get 4.