Passing an exception up the calling chain

Question

Was hoping for an explanation as to what it means to pass an exception up the calling chain by declaring the exception in my methods throws clause and why I would want to do tha

Answer 1

You can do it for example by not catching it in main(), but passing it to the piece of logic that called main(). In this case, it's trivial, as main() is your program's entry point...

You could also rewrite your method

void checkArray() throws ABException {
    for (int i = 0; i < charArray.length; i++) {
        check(charArray[i]);
    }
}

void check(char c) throws ABException {
    switch (c) {
        case 'a':
            throw new ABException();
        case 'b':
            throw new ABException();// creating the instance of the
                                    // exception anticipated
        default:
            System.out.println(c + " is not A or a B");
    }
}

Now it becomes more clear how checkArray() "passes the exception from check() up the calling chain"