Why does the c# compiler emit Activator.CreateInstance when calling new in with a generic type with a new() constraint?

Question

When you have code like the following:

static T GenericConstruct() where T : new()
{
    return new T();
}

The C# compiler insist

Answer 1

Interesting observation :)

Here is a simpler variation on your solution:

static T Create() where T : new()
{
  Expression> e = () => new T();
  return e.Compile()();
}

Obviously naive (and possible slow) :)