iOS - Unable to Upload media with Twitter/Fabric New SDK

Question

I want to post a photo to twitter from my iOS app. I can post a tweet without media but when i am trying to attach media it throws an error.

I am following twitter docu

Answer 1

Swift 4 latest

install pod file pod 'TwitterKit'

import TwitterKit

https://developer.twitter.com/en/docs/media/upload-media/api-reference/post-media-upload-init.html

func PostTweetToTwitter() {
        let twitter_USERID = UserDefaults.standard.string(forKey: Constants.Twitter.TWITTER_USER_ID)

        let url = URL(string: "http://www.tinyeyeimage.com/picture/Photos/149802345.png")
        let tweetImage = try? Data(contentsOf: url!)

        let tweetString = "Welcome to the Twitter world!!"

        let uploadUrl = "https://upload.twitter.com/1.1/media/upload.json"
        let updateUrl = "https://api.twitter.com/1.1/statuses/update.json"

        let imageString = tweetImage?.base64EncodedString(options: NSData.Base64EncodingOptions())


        let client = TWTRAPIClient.init(userID: twitter_USERID)

        let requestUploadUrl = client.urlRequest(withMethod: "POST", urlString: uploadUrl, parameters: ["media": imageString], error: nil)

        client.sendTwitterRequest(requestUploadUrl) { (urlResponse, data, connectionError) -> Void in
            if connectionError == nil {
                if let mediaDict = self.dataToJSON(data: (data! as NSData) as Data) as? [String : Any] {
                    let media_id = mediaDict["media_id_string"] as! String
                    let message = ["status": tweetString, "media_ids": media_id]

                    let requestUpdateUrl = client.urlRequest(withMethod: "POST", urlString: updateUrl, parameters: message, error: nil)

                    client.sendTwitterRequest(requestUpdateUrl, completion: { (urlResponse, data, connectionError) -> Void in
                        if connectionError == nil {
                            if let _ = self.dataToJSON(data: (data! as NSData) as Data) as? [String : Any] {
                                print("Upload suceess to Twitter")
                            }
                        }

                    })
                }
            }
        }
    }