How can a Windows Service determine its ServiceName?

Question

I\'ve looked and couldn\'t find what should be a simple question:

How can a Windows Service determine the ServiceName for which it was started?

Answer 1

ServiceBase.ServiceName property gives the compile-time name of service. If you specify a different name when installing the service, then ServiceName attribute will not give correct name. So, I had to use below code to obtain the service name of my service.

It's an alternative (without using LINQ) to NVRAM's method:

/**
 * Returns the service name of currently running windows service.
 */
static String getServiceName()
{
    ServiceController[] scServices;
    scServices = ServiceController.GetServices();

    // Display the list of services currently running on this computer.
    int my_pid = System.Diagnostics.Process.GetCurrentProcess().Id;

    foreach (ServiceController scTemp in scServices)
    {
        // Write the service name and the display name
        // for each running service.

        // Query WMI for additional information about this service.
        // Display the start name (LocalSytem, etc) and the service
        // description.
        ManagementObject wmiService;
        wmiService = new ManagementObject("Win32_Service.Name='" + scTemp.ServiceName + "'");
        wmiService.Get();

        int id = Convert.ToInt32(wmiService["ProcessId"]);
        if (id == my_pid)
        {
            return scTemp.ServiceName;
#if IS_CONSOLE
            Console.WriteLine();
            Console.WriteLine("  Service :        {0}", scTemp.ServiceName);
            Console.WriteLine("    Display name:    {0}", scTemp.DisplayName);

            Console.WriteLine("    Start name:      {0}", wmiService["StartName"]);
            Console.WriteLine("    Description:     {0}", wmiService["Description"]);

            Console.WriteLine("    Found.......");
#endif
        }
    }
    return "NotFound";
}

I was incorrectly trying to obtain the name of windows service as first line in main() without first calling ServiceBase.Run(). We must register our executable as service using ServiceBase.Run() before obtaining its name.

Ref.: http://msdn.microsoft.com/en-us/library/hde9d63a.aspx#Y320