PHP date format /Date(1365004652303-0500)/

Question

I am calling an API from where I am getting date /Date(1365004652303-0500)/, I don\'t understand what format this is. How is this date format called? I was not

Answer 1

This is what I'm using to parse timestamps from a Xero API. It accounts for:

• Negative timestamps, dates before the epoch.
• Timestamps with less than 10 digits (but on the epoch - time zero - not sure what that format would even look like)
• Fractions of a second.
• Optional timezone offset, both positive and negative.

Code:

if (preg_match('#^(/Date\()([-]?[0-9]+)([0-9]{3})([+-][0-9]{4})?(\)/)$#', $data, $matches)) {
    // Handle Xero API DateTime formats. Examples:
    // "/Date(1436961673000)/" - unix timestamp with milliseconds
    // "/Date(1436961673000+0100)/" - with an additional timezone correction
    // "/Date(-1436961673000-0530)/" - before the epoch, 1924 here
    //
    // RE matches for "/Date(1436961673090+0100)/":
    // [1] = (/Date\()          "/Date("
    // [2] = ([-]?[0-9]+)       "1436961673"    epoch seconds
    // [3] = ([0-9]{3})         "090"           milliseconds
    // [4] = ([+-][0-9]{4})?    "+0100" or ""   optional timezone
    // [5] = (\)/)              ")"

    $result = \DateTime::createFromFormat('U u', $matches[2] . ' ' . $matches[3] . '000')
        ->setTimezone(new \DateTimeZone($matches[4] ?: '+0000'));
}