Compile-time assertion?

Question

Is there a way I can assert that two constant expressions are equal at compile time?

e.g. I want this to cause a compile-time error

enum { foo=263,          


        

Answer 1

There is also the trick to use a switch (..) statement. Kind of old style though. The case entry foo == bar has to be compile time evaluated and if it happens to be false the switch statement will cause an error. The compiler will also reduce it to "nothing".

{ 
  bool x=false; 
  switch (x) {
  case foo == bar:
    break;
  case false:
    // Compile time test that foo == bar
    break;
}