Warn when using parameter marked as __unused

Question

Using the -Wunused-parameter flag, you can enforce __unused for unused parameters, as a compiler optimization. The following code causes two warnings:

#include &         


        

Answer 1

Another way to skin this cat is to remove (or comment out) the name of the parameter.

int main ( int argc, char ** /* argv */ ) {
    printf("hello world. there are %d args\n", argc);
    return 0;
}

Now the compiler won't warn about argv being unused, and you can't use it, because it has no name.