If parenthesis has a higher precedence then why is increment operator solved first?

Question

I have a single line code,

int a = 10;
a = ++a * ( ++a + 5);

My expected output was 12 * (11 + 5) = 192 ,but I got 187

Answer 1

  int a = 10;
  a = ++a * ( ++a + 5);

above kind of expressions are always evaluated in left to right fashion be it C or JAVA

in this case it is solving like this 11*(12+5) which results in 11*17 = 187 // w.r.t java

but if it we solve the same expression w.r.t C-language

then the answer gets changed as the way of evaluation changes

in c first pre-increment/pre-decrement happens ,so if "N" no of times pre inc/dec are there in the expression then inc/dec will happen first "N" no of times

then the same value will be substituted in each ocurrence of the variable in the expression and the expression value is calculated and after that post increment/decrement happens

i.e a gets incremented to 11 then again 12 as there are two incrementation for a in the expression and then the expression is evaluated as

12*(12+5)=12*17=204 //w.r.t C-language