Get Last 2 Decimal Places with No Rounding

Question

In C#, I\'m trying to get the last two decimal places of a double with NO rounding. I\'ve tried everything from Math.Floor to Math.Truncate and nothin

Answer 1

A general solution:

    public static double SignificantTruncate(double num, int significantDigits)
    {
        double y = Math.Pow(10, significantDigits);
        return Math.Truncate(num * y) / y;
    }

Then

    double x = 5.3456;
    x = SignificantTruncate(x,2);

Will produce the desired result x=5.34.