Sorting a list with stream.sorted() in Java

Question

I\'m interested in sorting a list from a stream. This is the code I\'m using:

list.stream()
    .sorted((o1, o2)->o1.getItem().getValue().compareTo(o2.get         


        

Answer 1

This is not like Collections.sort() where the parameter reference gets sorted. In this case you just get a sorted stream that you need to collect and assign to another variable eventually:

List result = list.stream().sorted((o1, o2)->o1.getItem().getValue().
                                   compareTo(o2.getItem().getValue())).
                                   collect(Collectors.toList());

You've just missed to assign the result