Incrementor logic

Question

I\'m trying to get deeper with post and pre incrementors but am a bit stuck with the following expression :

public static void main(String[] args) {
    int i         


        

Answer 1

Ok, let's break down every thing:

int i = 0; // i = 0, no big deal

Then starting into the most inner parenthesis:

(i+=2 + --i)

• it first decrement i and use the result (-1)
• then add 2 (-1+2=1)
• and add the result to i (which is 0 at the start of the operation) (0+1=1=i)

At the end, the first decrement is ignored by the reassignation.

Next parenthesis:

i+= (++i + previous_result - ++i)

• it increase the i ( with ++i) at two points
• then the operation becomes (i+1) + previous_result - (i+2) (notice how the increment are not simultaneous) that gives 2 + 1 - 3 = 0.
• the result of the operation is added to the initial i (0)

Again the increment will get discard by the reassignation.

finally:

i = previous_result

Which gives 0 :)