Why aren't Integers cached in Java?

Question

I know there are similar posts on the topic, but they don\'t quite address my question. When you do:

Integer a = 10;
Integer b = 10;
System.out.println(\"a =         


        

Answer 1

For Integer objects use the a.equals(b) condition to compare.

The compiler will not do the unboxing for you while you compare, unless you assign the value to a basic type.