Why aren't Integers cached in Java?

Question

I know there are similar posts on the topic, but they don\'t quite address my question. When you do:

Integer a = 10;
Integer b = 10;
System.out.println(\"a =         


        

Answer 1

In Java, every time you call the new operator, you allocate new memory and you create a new object. That's standard language behavior, and to my knowledge there is no way to bypass this behavior. Even standard classes have to abide by this rule.