Test the following code:
#include
#include
main()
{
const char *yytext=\"0\";
const float f=(float)atof(yytext);
siz
Use the compiler flag -fno-strict-aliasing.
With strict aliasing enabled, as it is by default for at least -O3, in the line:
size_t t = *((size_t*)&f);
the compiler assumes that the size_t* does NOT point to the same memory area as the float*. As far as I know, this is standards-compliant behaviour (adherence with strict aliasing rules in the ANSI standard start around gcc-4, as Thomas Kammeyer pointed out).
If I recall correctly, you can use an intermediate cast to char* to get around this. (compiler assumes char* can alias anything)
In other words, try this (can't test it myself right now but I think it will work):
size_t t = *((size_t*)(char*)&f);