Spark DataFrame: count distinct values of every column

Question

The question is pretty much in the title: Is there an efficient way to count the distinct values in every column in a DataFrame?

The describe method provides only th

Answer 1

In pySpark you could do something like this, using countDistinct():

from pyspark.sql.functions import col, countDistinct

df.agg(*(countDistinct(col(c)).alias(c) for c in df.columns))

Similarly in Scala :

import org.apache.spark.sql.functions.countDistinct
import org.apache.spark.sql.functions.col

df.select(df.columns.map(c => countDistinct(col(c)).alias(c)): _*)

If you want to speed things up at the potential loss of accuracy, you could also use approxCountDistinct().