How do i pass an array function without using pointers

Question

I have been asked in an interview how do you pass an array to a function without using any pointers but it seems to be impossible or there is way to do this?

Answer 1

Put the array into a structure:

#include 
typedef struct
{
  int Array[10];
} ArrayStruct;

void printArray(ArrayStruct a)
{
  int i;
  for (i = 0; i < 10; i++)
    printf("%d\n", a.Array[i]);
}

int main(void)
{
  ArrayStruct a;
  int i;
  for (i = 0; i < 10; i++)
    a.Array[i] = i * i;
  printArray(a);
  return 0;
}