sum (adding 2 numbers ) without plus operator

Question

Can anyone explain the logic how to add a and b?

#include 

int main()
{
     int a=30000, b=20, sum;
     char *p;
             


        

Answer 1

p[b] is the b-th element of the array p. It's like writing *(p + b).

Now, when adding & it'll be like writing: p + b * sizeof(char) which is p + b.
Now, you'll have (int)((char *) a + b) which is.. a + b.

But.. when you still have + in your keyboard, use it.

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As @gerijeshchauhan clarified in the comments, * and & are inverse operations, they cancel each other. So &*(p + b) is p + b.